The vector position of a 3.1 g particle moving in the xy plane varies in time according to r1 = (3i + 3j)t+2jt^2 where t is in seconds and is in centimeters. At the same time, the vector position of a 5.35 g particle varies as r2 = 3i − 2it^2 − 6jt.Determine the vector position of the center of mass at t =2.4Determine the linear momentum of the system at t=2.4Determine the velocity of the center of mass at t=2.4Determine the net force exerted on the two particle system at t=2.4
